10 g of ice at 0 0 C is mixed with 100 g of water at 50 0 C. What is the resultant temperature of mixture?
Text Solution
Verified by ExpertsThe correct answer is:
D
Heat given by water = 100 × (50– θ )
& heat taken by ice = 10 × 80 + 10 ( θ – 0)
⇒ 100 × (50 – θ ) = 80 + 10 ( θ )
⇒ θ = 38.2 0 C
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